Question

If the sum of the squares of zeros of the polynomial 6x square + x + k is 25/36, find the value of k​

Answer 1

Answer:

-2

Step-by-step explanation:

The zeros of 6x^2 + x + k can be found via the quadratic formula:

x = (-1 +/- √(1 - 24k))/12

(√(1 - 24k) - 1)^2/144 + (√(1 - 24k) + 1)^2/144 = 25/36

(2 - 24k - 2√(1 - 24k) + 2 - 24k + 2√(1 - 24k)) = 100

4 - 48k = 100 => k = -2