Question

If the sum of the term of progression 4,7,10.... Is 714 find the number of term in a progression

Answer 1

Answer:

S=n/2[2a+(n-1)d]

Step-by-step explanation:

S=714

a=4

d=3; second term minus first term

put it in formula

714=n/2[2×4+(n-1)×3]

1428/n=8+3n-3

1428=3n^2+5n

we have got a quadratic equation

by solving sri dharacharya formula

we got answer