Question

यदि 8, 10, 9, 11 व X का समांतर माध्य 10 हो तो X का मान ज्ञात कीजिए ।

Answer 1

$\textsf{I think your question is:}$

$\textsf{If the arithmetic mean of 8, 10, 9, 11 and X is 10, find the value of X}$

$\textbf{Concept used:}$

$\text{The arithmetic mean of n numbers x_1,x_2,x_3....x_n is }$

$\displaystyle\frac{\Sigma{x_i}}{n}$

$\textbf{Given:}$

$\text{Arithmetic mean}=10$

$\displaystyle\frac{\Sigma{x_i}}{n}=10$

$\displaystyle\frac{8+10+9+11+X}{5}=10$

$\displaystyle\frac{38+X}{5}=10$

$\displaystyle\;38+X=50$

$\displaystyle\;X=50-38$

$\implies\displaystyle\;X=12$

$\therefore\textbf{The value of X is 12}$

Find more:

1.The mean of 7 numbers is 24 if out of these 7 numbers the mean of first four number is 23 and the mean of the last four number is 25.5 then find the fourth number

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2.If the mean of 17, 19, 24, 15, 18, 16, x, 14 is 17. ſind the value of x​

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Answer 2

Answer:

\textbf{Concept:}Concept:

\text{If } |x|=u, \text{ then} \;x=\pm\;uIf ∣x∣=u, thenx=±u

\textbf{Given:}Given:

|2a-3|=3a+2∣2a−3∣=3a+2

\text{Using the given concept,}Using the given concept,

2a-3=\pm(3a+2)2a−3=±(3a+2)

\text{case(i):}case(i):

2a-3=3a+22a−3=3a+2

-2-3=3a-2a−2−3=3a−2a

\implies\bf\;a=-5⟹a=−5

\text{case(ii):}case(ii):

2a-3=-(3a+2)2a−3=−(3a+2)

2a-3=-3a-22a−3=−3a−2

2a+3a=3-22a+3a=3−2

5a=15a=1

\implies\bf\;a=\frac{1}{5}⟹a=51

\text{But a=-5 does not satisfy the given equation }But a=-5 does not satisfy the given equation 

\therefore\text{The solution is }\bf\;a=\frac{1}{5}∴The solution is a=51