If the sum of the zero of quadratic polynomial ky square +2y-3k is equal to twice their product find the value of k
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Let the roots of the equation be α and β
according to the question
2(Product of roots)= Sum of roots
2αβ=α+β --------(1)
αβ= -3k/k -------- (2)
α+β=-2/k ----------(3)
so from 1, 2 and 3
we get k= 1/3
Hope my answer is correct :)
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