Question

If the sum of the zeroes is sin 90° and product of the xeroes is 2 coso" then
find the quadratic polynomial.​

Answer 1

Step-by-step explanation:

$given \\ \alpha + \beta = \sin90 \\ where \: \sin90 = 1 \\ \alpha + \beta = 1 = \frac{ - ( - 1)}{1} \\ \alpha \beta = 2 \cos0 \\ where \: cos 0 = 1 \\ \alpha \beta = 2(1) = 2 \\ general \: formula \: is \\ ( {x}^{2} - ( \alpha + \beta )x + \alpha \beta ) \\ = ( {x}^{2} - (1)x + 2) \\ = {x }^{2} - x + 2 \\ is \: your \: polynomial$

Answer 2

Answer:

Here is your answer

Hope this helps you