Question

If the sum of the zeroes of (a+1) x^2 + (2a+3) x + (3a+4) is (-1) find the product of their
zeroes.

Answer 1

Answer:

a = 4

Step-by-step explanation:

the sum of its zeros = -b/a

-2a+3/a+1 = -1

-2a+3 = -a-1

-2a+a = -1 -3

-a = -4

a = 4

a = (a+1) = 4+1 = 5

b = (2a+3) = 2*4+1 =8+1 = 9

c = (3a+4) = 3*4+4 = 12+4 =16

the equation formed is 5x^2-9x+16

the product of its zeros = c/a

16/5