Math, asked by kohli560, 11 months ago

If the sum of the zeroes of kx^2+2x+3k is equal to their product then ,find the value of k .

Answers

Answered by anu99956
35

hey mate here I m here for Ur answer

equation is kx²+2x+3k

we know that

sum of zeros= product of zeros

-b/a = c/a

putting the value of a,b,c

-2/k= 3k/k

k in denominator will be cancelled

-2=3k

k=-2/3

I hope it helps

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