If the sum of the zeroes of kx^2+2x+3k is equal to their product then ,find the value of k .
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hey mate here I m here for Ur answer
equation is kx²+2x+3k
we know that
sum of zeros= product of zeros
-b/a = c/a
putting the value of a,b,c
-2/k= 3k/k
k in denominator will be cancelled
-2=3k
k=-2/3
I hope it helps
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