Math, asked by vedantitidke12, 7 months ago

If the sum of the zeroes of the polynomial 2x3-3kx2+4x-5 is 12 then the value of k is​

Answers

Answered by shaziyamohammad80
1

Answer:

I think it is helpful

Step-by-step explanation:

A quantity a is called zero of a polynomial p(x) if p(a) = 0 . Here, we have p(x) = 2x^3 -3kx^2 + 4x -5 . Let a, b, c be the three zeros of p(x) ,then it is given that (a+b+c) = 6 . But from the equation p(x) = 0, we get, a+ b + c = 3k/2 which implies 3k/2 = 6 ==>k = 4 .

Answered by devanshidwivedi98
0

Step-by-step explanation:

in cubic polynomial sum of zeroes is -b/a

in this polynomial sum of zeroes is 12

so

=-(-3k)/2=12

3k =24

k =8

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