Question

if the sum of the zeroes of the polynomial f(x)=2x³-3kx²+4x-5 is 6, then find the value of k

Answer 1

f(6)=2(216)-3k(36)+4(6)-5=0
    =432-3k(36)+24-5=0
    =--k(108)+19= -432
    = -k+19= -432/108
     = k+19= 4
     = k=19+4=20
   k=20

Answer 2

Answer:

Step-by-step explanation:

K=4

The equation is cubic

Therefore, sum of zeroes = -b/a

It is given that -b/a = 6

-b= 3k

a= 2

3k/2 = 6

3k=12

K = 12/3

K= 4