y= 3x/2+2/3
in graph in linear equation
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y = 3x/2 + 2/3
Now we have to take three values of x & y so that we can plot in a graph:
Putting value of x as 0, the value of y we get as,
y = 3*0/2 + 2/3
y = 2/3 = 0.66 = 0.7
So we get one point which is x=0, y= 0.7
Putting the value of x as 1, the value of y we get as:
y = 3/2*1 + 2/3
y = (9+4)/6 = 13/6 = 2.2
So we get the second point which is x=1 , y=2.2
Putting the value of x as 2, the value of y we get as:
y = 3/2*2 + 2/3
y = (9+2)/3 = 11/3 = 3.66 = 3.7
So we get the third point which is x=2, y=3.7
Now plot the values in the graph accordingly, in the respective x & y axis.
Now we have to take three values of x & y so that we can plot in a graph:
Putting value of x as 0, the value of y we get as,
y = 3*0/2 + 2/3
y = 2/3 = 0.66 = 0.7
So we get one point which is x=0, y= 0.7
Putting the value of x as 1, the value of y we get as:
y = 3/2*1 + 2/3
y = (9+4)/6 = 13/6 = 2.2
So we get the second point which is x=1 , y=2.2
Putting the value of x as 2, the value of y we get as:
y = 3/2*2 + 2/3
y = (9+2)/3 = 11/3 = 3.66 = 3.7
So we get the third point which is x=2, y=3.7
Now plot the values in the graph accordingly, in the respective x & y axis.
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here is the graph for your need
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