If the sum of the zeroes of the polynomial kx^2
+ 2x +3k is equal to their product, find the
value of k
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Hey there !!!
p(x) = kx² + 2x + 3k
a = k
b = 2
c = 3k
Sum of zeroes = -b/a = -2/k
Product of zeroes = c/a = 3k/k = 3
Given :-
sum of zeroes = product of zeroes
-2/k = 3
-2 = 3k
k = -2/3
Hope this Helps you !!
p(x) = kx² + 2x + 3k
a = k
b = 2
c = 3k
Sum of zeroes = -b/a = -2/k
Product of zeroes = c/a = 3k/k = 3
Given :-
sum of zeroes = product of zeroes
-2/k = 3
-2 = 3k
k = -2/3
Hope this Helps you !!
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