If the sum of the zeroes of the polynomial p(x)=(a+1)x2+(2a+3)x+(3a+4) is -1 find the product of its zeroes
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Let the zeroes be l & k
so,
l+k=-2a-3/a+1
-1=-2a-3/a+1
-a-1=-2a-3
a=-2
now,
lk=3a+4/a+1
putting a=-2, we get,
-2/-1=lk
lk=2
so,
l+k=-2a-3/a+1
-1=-2a-3/a+1
-a-1=-2a-3
a=-2
now,
lk=3a+4/a+1
putting a=-2, we get,
-2/-1=lk
lk=2
umachy71:
it was given that l+k=-1
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