If the sum of the zeroes of the polynomial p(x) equal to (a+1) x square+ (2a+3) x + (3a+4) is -1 then find the product of it's zeroes.
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Answer:
product of zeroes.=2
Step-by-step explanation:
p(x)=(a+1)x²+(2a+3)x+(3a+4)
Let α,β are zeros
so α+β=-(2a+3)/(a+1)=-1
so 2a+3=a+1
a =1 - 3= -2
Now αβ=(3a+4) / (a+1)
=-3(-2)+4 / -2+1
=-6+4/-1
=-2/-1
=2
product of it's zeroes.=2
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