Question

If the sum of the zeroes of the quadratic polynomial 3x-kx+6 is 3, then find
the value of k.​

Answer 1

Answer:

9

Step-by-step explanation:

p(x) = 3x2 - kx + 6

sum of the zeroes = 3 = -(Coefficient of x)/(Coefficient of x2)

3 = -((-k)/3)

k = 9

Answer 2

Answer:

$3x {}^{2} - \: kx \: + 6 = 0$

$sum \: of \: zeroes \: = 3$

$\alpha + \beta = 3$

$\frac{ - b}{a \:} = 3$

$\frac{ - ( - k)}{3} = 3$

$\frac{k}{3} = 3$

$k = 9$

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