Question

If the sum of the zeroes of the quadratic polynomial 3x2
-kx+6 is 4, then find the
value of k.

Answer 1

Answer:

$\alpha + \beta = 4 \\ \alpha + \beta = - ( - k) \div 6 \\ so \\ 4 = k \div 6 \\k = 6 \times 4 \\ k = 24$

hope it helps..

Answer 2

Answer:

$\alpha + \beta = 4 \\ \alpha + \beta = - \frac{b}{a} \\ 4 = - \frac{ - k}{3} \\ 4 = \frac{k}{3} \\ k = 12$