if the sum of the zeroes of the quadratic polynomial f(t) = kt2+2t+3k is equal to their product find the value of k
Answers
Answer:
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Step-by-step explanation:
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Given,
- f(t) = kt²+2t+3k is given.
- The Sum of the zeroes of the quadratic polynomial is equal to their product.
To find,
- We have to find the value of k.
Solution,
We can simply find the value of k by using the following formulas:
Sum of zeroes of a quadratic polynomial = -b/a (*)
Product of zeroes of a quadratic polynomial = c/a (**)
The given quadratic polynomial is f(t) = kt²+2t+3k
Using (*), we get
Sum of the zeroes = -b/a
= -2/k
Using (**), we get
Product of the zeroes = c/a
= 3k/k
= 3
According to the given condition,
The Sum of the zeroes of the quadratic polynomial is equal to their product.
then, -2/k = 3
By cross multiplying, we get
-2 = 3k
-2/3 = k
Hence, if the sum of the zeroes of the quadratic polynomial f(t) = kt²+2t+3k is equal to their product, then the value of k is -2/3.