Math, asked by basketballbonap26508, 1 year ago

if the sum of the zeroes of the quadratic polynomial f(t) = kt2+2t+3k is equal to their product find the value of k

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Answered by nanupriyapathak
72

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Answered by SteffiPaul
16

Given,

  • f(t) = kt²+2t+3k is given.
  • The Sum of the zeroes of the quadratic polynomial is equal to their product.

To find,

  • We have to find the value of k.

Solution,

We can simply find the value of k by using the following formulas:

                Sum of zeroes of a quadratic polynomial = -b/a    (*)

               Product of zeroes of a quadratic polynomial = c/a (**)

The given quadratic polynomial is f(t) = kt²+2t+3k

Using (*), we get

       Sum of the zeroes = -b/a

                                       = -2/k

Using (**), we get

      Product of the zeroes = c/a

                                            = 3k/k

                                            = 3

According to the given condition,

The Sum of the zeroes of the quadratic polynomial is equal to their product.

then,            -2/k = 3

               By cross multiplying, we get

                     -2  = 3k

                   -2/3 = k

Hence, if the sum of the zeroes of the quadratic polynomial f(t) = kt²+2t+3k is equal to their product, then the value of k is -2/3.

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