Question

If the sum of the zeros of the polynomial f(x) =2x^3 -3kx^2+4x-5 is 6, then the value of k is __

Answer 1

Answer:

k=4

Step-by-step explanation:

$2 {x}^{3} - 3k {x}^{2} + 4x - 5 \\ sum \: of \: zeros \: = 6 \\ \frac{3k}{2} = 6 \\ k = 4 \\ \\ hope \: it \: will \: help \: you \:$