if the sum of the zeros of the quadratic polynomial f t is equal to k p square + 2 T + 3 K is equal to their product find the value of k
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Answer:
Let F(t)= kt2 +2t +3t
there, a=k
b=2
c=3k
Give
sum of zeros= -b/c
alpha+beta=-2/k
product of zeros=c/a
alpha*beta=3k/k
Now,
alpha+beta=abpha*beta
3=-2/k
k=-2/3
so, the value of K= -2/3
Step-by-step explanation:
glakshmijaya:
good
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