If the sum of the zeros of the quadratic polynomial f(x)=kx2 +2x+3k is equal to their product find the value of k
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Let f(x) = kx2 + 2x + 3k
Here a = k, b = 2 and c = 3k
Sum of zeroes, α + β = -b/a = -(2)/k = -2/k
Product of zeroes, αβ = c/a = 3k/k = 3
Given,
Sum of zeroes = Product of zeroes
-2/k = 3
k = -2/3
So, value of k = -2/3
Here a = k, b = 2 and c = 3k
Sum of zeroes, α + β = -b/a = -(2)/k = -2/k
Product of zeroes, αβ = c/a = 3k/k = 3
Given,
Sum of zeroes = Product of zeroes
-2/k = 3
k = -2/3
So, value of k = -2/3
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