If the sum of the zeros of x square + px + 1 is 9 then p is
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1
let roots of the above equation be a and b ..
given sum of roots =9 =-b/a
9=-p/1
p=-9
hope it helps. sorry if I was wrong
Steph0303:
You are right :)
Answered by
3
Answer:
p = -9
Step-by-step explanation:
In a Quadratic Equation, Sum of Zeros can be written as : -b / a
Here, 'b' refers to the coefficient of 'x' term and 'a' refers to the coefficient of 'x²' term.
According to the given question,
⇒ x² + px + 1 = 0
Here, 'a' = 1, 'b' = p
Sum = 9
Substituting the values, we get,
⇒ Sum = -b / a
⇒ 9 = -p / 1
⇒ -p = 9
⇒ p = -9
Hence the value of p is -9.
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