If the sum of thirteen consicutive integer is 169 then what is the tenth integer
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Total no. of integers = 13
Let the smallest integer = x
Sum of the 13 integers = 169
(x)+(x+1)+........+(x+12)
= 13x + (1+2+3+......+11+12)
= 13x + 78
13x + 78 = 169
13x = 169 - 78
13x = 91
x = 91/13
x = 7
Tenth integer = 7 + 9
= 16
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