If the sum of thre consecutive multiples, 9 is 108, what the average of multiples ?
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2
Answer:
Average of consecutive multiples of 9 is 36.
Step-by-step explanation:
Let the required consecutive multiples of be 9a, 9b and 9c.
Given,
Sum of these 3 multiples is 108.
= > 9a + 9b + 9c = 108 { Dividing both sides by 3 }
= > ( 9a + 9b + 9c ) / 3 = 108 / 3 { LHS represents the average of 9a , 9b , 9c which are the multiples of 9 }
= > Average of multiples of 9 = 36
Thus, average of consecutive multiples of 9 is 36.
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Step-by-step explanation:
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