if the sum of three consecutive even integer is 36 thn largest integer is?
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Heya !!!
it is given that sum of the consecutive even numbers is 36.
We have to find the numbers
...
let the first number be x.
then the second number will be x+2.
Also, the third number will be x + 2 + 2= X+4.
According to the question,
their sum is 36.
So,
X + X +2 + X + 4 = 36
3x + 6 = 36
3x = 30
X = 10.
Hence, the first digit is 10.
second digit = X +2 = 12.
third digit = X +4 = 14.
Hence the three consecutive ever digits whose sum is 36 are 10, 12, and 14.
it is given that sum of the consecutive even numbers is 36.
We have to find the numbers
...
let the first number be x.
then the second number will be x+2.
Also, the third number will be x + 2 + 2= X+4.
According to the question,
their sum is 36.
So,
X + X +2 + X + 4 = 36
3x + 6 = 36
3x = 30
X = 10.
Hence, the first digit is 10.
second digit = X +2 = 12.
third digit = X +4 = 14.
Hence the three consecutive ever digits whose sum is 36 are 10, 12, and 14.
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