Question

if the sum of three consecutive integers is less than 80 find the largest possible value of the largest integer ​

Answer 1

Answer:

26,27,28 81=(n-1)+n+(n+1)

Answer 2

The largest possible value of the largest integer is 27.67

Step-by-step explanation:

let the first integer be x

second integer be (x+1)

third integer be (x+2)

then according to the question,

the sum of three consecutive integers is less than 80

x+x+1+x+2 < 80

3x+3  < 80

3x < 80-3

3x  < 77

x <$\frac{77}{3}$

x< 25.67

first integer x  = 25.67

second integer be (x+1) = 25.67 +1 = 26.67

third integer be (x+2) = 25.67 +2 = 27.67

hence,

The largest possible value of the largest integer is 27.67

#Learn more:

The sum of 3 consecutive even integers is less than 83. what isthe largest value possible for the smallest integer?

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