Question

If the sum of three consecutive multiples of 3 is 369, find the three numbers.
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Answer 1

Answer:

Hence the three no. is 120,123 and 126

Answer 2

Step-by-step explanation:

369 divide by 3

369\3=123

now let the smallest no:-x

so x +( x+1 ) + ( x + 2 )=123

x + x + 1 + x + 2= 123

3x + 3 = 123

3x = 123-- 3

x=120\3

x=40

so the first number is =40×30=120

second number is =40×1+3=126

third number is 40 + 2 × 3 =126