Question

*If the sum of three consecutive positive integers is 45, which is the largest number of them?*

1️⃣ 14
2️⃣ 18
3️⃣ 16
4️⃣ 20​

Answer 1

Step-by-step explanation:

sum of three consecutive positive integers =45

the numbers x,x+1,x+2

x+(x+1)+(x+2)=45

3x=42

x=14

thn largest number is x+2=16

Answer 2

Question :- If the sum of three consecutive positive integers is 45, which is the largest number of them?*

1) 14

2) 18

3) 16

4) 20

Solution :-

Let us assume that, three consecutive positive integers are ,

• first integer = x
• second integer = (x + 1)
• third integer = (x + 1) + 1 = (x + 2)

given that, sum of all three is 45 .

so,

→ x + (x + 1) + (x + 2) = 45

→ x + x + x + 1 + 2 = 45

→ 3x + 3 = 45

→ 3x = 45 - 3

→ 3x = 42

dividing both sides by 3, we get,

→ x = 14 .

therefore,

→ Largest integer = Third integer = (x + 2) = 14 + 2 = 16 (Option 3) (Ans.)

Hence, Largest positive integer is 16.

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