if the sum of three consecutive terms of AP is 48 and the product of first and last term is 252 then find d
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Step-by-step explanation:
always the three consecutive number is in the form of (a-d) , a , (a+d)
so the sum of three terms is = 48
(a-d) + a+(a+d) = 48
3a=48
a=48/3
a=16
now the product of first and third term is = 252
(a-d) x (a+d) = 252
a²-d²= 252
(16)²-d²=252
256-d²=252
d² = 256 - 252
d²=4
d=√4
d=2
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