Question

If the sum of three no in ap is 27 and the product of first and last is 77 then the number is

Answer 1

Answer:-

7 , 9 , 11

Given :-

Sum of three number in AP is 27.

Product of first and last is 77.

To find :-

The three number.

Solution:-

Let the three number in AP be a ,

Let the three number in AP be a , a + d and a - d .

Where a is the first term and d is the common - difference.

A/Q

$a + a +d + a-d = 27$

→$3a = 27$

→$a = \dfrac{27}{3}$

→$a = 9$

Now ,

$(a +d) (a-d) = 77$

→$a^2 - d^2 = 77$

→$(9)^2 - d^2 = 77$

→$81 -77 = d^2$

→$d^2 = 4$

→$d = 2$

The three numbers in AP will be :-

→a = 9

→a + d

= 9 + 2

= 11

→a - d

=9 - 2

= 7

Answer 2

May the solution help u
Thanks me if u liked the answer