If the sum of three whole numbers taken in pairs are 43, 50 and 63, then the largest five digit number divisible by the three whole numbers arranged in ascending order leaves the remainder 11, 24 and 31 respectively is
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Different scores that are possible as a combination of both dices are thrown -
(0,0) = 0
(0,1) = 1
(0,6) = 6
(1,1) = 2
(1,6) = 7
(6,6) = 12
To get a score of 7, one dice must show 1 and one dice must show 6.
Probability of dice getting 1 = 3/6 = 1/2.
Probability of dice getting 6 = 2/6 = 1/3.
Thus probability of getting score 7 is =
1/2 * 1/3 + 1/2*1/3 = 1/3.
Step-by-step explanation:
Different scores that are possible as a combination of both dices are thrown -
(0,0) = 0
(0,1) = 1
(0,6) = 6
(1,1) = 2
(1,6) = 7
(6,6) = 12
To get a score of 7, one dice must show 1 and one dice must show 6.
Probability of dice getting 1 = 3/6 = 1/2.
Probability of dice getting 6 = 2/6 = 1/3.
Thus probability of getting score 7 is =
1/2 * 1/3 + 1/2*1/3 = 1/3.
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