If the sum of two consecutive numbers of reciprocal of 12 upon 35 find those numbers
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Answer:
Let the numbers be x and x+2
Thus,
x
1
+
(x+2)
1
=
35
12
35(x+2)+35x=12x(x+2)
12x
2
−46x+70=0
6x
2
−23x+35=0
(6x+7)(x−5)=0
x=−
6
7
x=5
Since x is an integer so, x=5
Therefoe numbers are 5 and 7
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