Question

. If the sum of two consecutive odd numbers is 228, find the numbers.

Answer 1

LET FIRST ODD NUMBER BE = X

LET THE OTHER ODD NUMBER BE=X+2(because x+1 will be even number )

SO OUR EQUATION WILL BE= X+X+2=228  

                                                  =2X+2=228

                                                  =2X=228-2

                                                   =2X=226

                                                    =X= $\frac{226}{2}$

                                                  =X=113

SO ONE ODD NUMBER =113

SECOND ODD NUMBER =113+2=115

                                                 

Answer 2

$\large {\maltese {\textsf {\textbf {\underline { Given :}}}}}$

• Sum of consecutive odd numbers = 228

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎

$\large {\maltese {\textsf {\textbf {\underline { To \; find :}}}}}$

• The consecutive numbers.

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎

$\large {\maltese {\textsf {\textbf {\underline { Solution :}}}}}$

• Let's assume the numbers :-ㅤ‎

ㅤ‎ㅤ‎ㅤ‎ㅤ• x & x + 2

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎

• According to the question :-

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎

$\implies \sf {x + x + 2 = 228}$

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎

$\implies \sf {2x + 2 = 228}$

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎

$\implies \sf {2x = 228 - 2}$

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎

$\implies \sf {2x = 226}$

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎

$\implies \sf {x = \dfrac {226}{2}}$

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎

$\implies \sf {x = 113 }$

.

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎

Therefore, the numbers are :-

• x = 113

• x + 2 = 113 + 2 = 115