if the sum of two digit number and the number obtained by reversing the digit is 55 ,find the sum of the digits of the two digit number
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10x+y+10y+x=55 i think something is missing
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Answer:-
- The sum of the digits of the two digit number (x + y) is 5.
Solution:-
Let:-
- The digit in the tenth place be y.
- The digit in the one's place be x.
Then:-
- Original number is 10y + x.
According to Question:-
On reversing the digit the number is 10x + y.
Now:-
We can solve the equation easily,
=> 10y + x + 10x + y = 55
=> 11y + 11x = 55...........(i)
Now divide the equation (i) by 11,
=> 11y + 11x = 55
=> 11y/11 + 11x/11 = 55/11
=> y + x = 5
Therefore:-
The sum of the digits of the two digit number (x + y) is 5.
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