if the sum of two digit number and the number obtained by reversing the digit is 44 find the sum of the digit of the two digit number
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Ones Digit =x
Tens digit=10x
Original no. =10x+x
=11x
by reversing
ones digit =x
Tens digit=10x
New no. =10x+x
=11x
A. T. Q
11x+11x=44
22x=44
x=2
Sum of 2 digit=11x
11*2
=22
harsimransingh4548:
hello ji
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Answer
Original Number = 10x + y
Reversed number = 10y + x
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