if the sum of two number is 3 and the sum of their square is 12 then their product equal to?
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Step-by-step explanation:
Given:-
The sum of two numbers is 3 and the sum of their squares is 12.
To find:-
The value of their product of the two numbers ?
Solution:-
Let the numbers be X and Y
The sum of two numbers = 3
X+Y = 3 -----------------(1)
Sum of their squares = 12
X^2 + Y^2 = 12 -------(2)
On squaring the equation (1) both sides then
=>(X+Y)^2 = 3^2
We know that
(a+b)^2 = a^2 +2ab +b^2
=>X^2 +2XY +Y^2 = 9
=>(X^2+y^2) +2XY = 9
=>12 + 2XY = 9 (from (1))
=>2XY = 9-12
=>2XY = -3
=>XY = -3/2
The product of two numbers = -3/2
Answer:-
The product of two numbers = -3/2
Used formula:-
- (a+b)^2 = a^2 +2ab +b^2
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