if the sum of two numbers is 10 and sum of there reciprocal is 5/12 the number would be
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let x and y be 2 integers
x+y=10----------->1 and (1/x)+(1/y)=5/12------------>2
from 2 we get (x+y)/xy=5/12
i.e, 12(x+y)=5xy
from 1 we get x+y=10
5xy=120
xy=24
from this we get x=24/y----------->3
on substituting this equation in x+y=10 we get (24/y)+y=10
from this we get y²-10y+24=0
hence we will get y=6 or y=4
if y=6 then x=4
if x=4 then y=6
hence these 2 integers are 6 and 4
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