Question

If the sum of two numbers is 55 and the h.C.F. And l.C.M. Of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to:



a.55

Answer 1

Here is your answer

$\rule{137}{2}$

Let the numbers be x and y

x + y = 55

AND

x * y = 5 * 120

= 600

The required sum = $\frac{1}{x}$ + $\frac{1}{y}$

= $\frac{x+y}{xy}$

= $\frac{55}{600}$

By cancelling the numbers by 5, we get :-

$\frac{11}{120}$

∴ The answer is $\frac{11}{120}$

Answer 2

HEY MATE HERE IS YOUR ANSWER

__________________↙️ ↙️_______

Let the number be x and y.

$\huge \bold = > x + y = 55$

$\huge = > x \times y = 5 × 120$

$\huge = > 600$

The required sum

$= >\huge \: \frac{1}{x} + \frac{1}{y}$

$\huge = > \frac{x + y}{xy}$

$\huge = > \frac{55}{600}$

By cut the numbers on the table of 5 we get,

$\huge = = > > \: \frac{11}{120}$
___________↙️___________=____

Hope it will help you

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