If the sum of two positive numbers is 108 and the difference of those number is 8 then find those numbers
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x+y=108
x-y=8
by solving we get x=58 and y=50
x-y=8
by solving we get x=58 and y=50
Answered by
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Let two numbers be x and y
According to question
x + y = 108
x - y = 8 …………[1]
Add both the equations
x + y + x - y = 108 + 8
2x = 116
x = 58
If x = 58 then from equation [1] y = 58 - 8 = 58
The two numbers are 58 and 50
According to question
x + y = 108
x - y = 8 …………[1]
Add both the equations
x + y + x - y = 108 + 8
2x = 116
x = 58
If x = 58 then from equation [1] y = 58 - 8 = 58
The two numbers are 58 and 50
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