if the sum of zero of a quadratic polynomial p(x)=kx^2+2x-3k is equal to twice their product . find the value of k.
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Let f(x) = kx2 + 2x + 3k.
Here a = k, b = 2 and c = 3k.
Sum of zeroes, α + β = -b/a = -(2)/k = -2/k.
Product of zeroes, αβ = c/a = 3k/k = 3.
Given,.
Sum of zeroes = Product of zeroes. -2/k = 3. k = -2/3.
So, value of k = -2/3.
Here a = k, b = 2 and c = 3k.
Sum of zeroes, α + β = -b/a = -(2)/k = -2/k.
Product of zeroes, αβ = c/a = 3k/k = 3.
Given,.
Sum of zeroes = Product of zeroes. -2/k = 3. k = -2/3.
So, value of k = -2/3.
girlishstyle:
thnks
welcome and thanks :-)
but the value of c is wrong
it is -3k
and u have written +3k
so by this the value of k will be +2/3
yeah
right
okk
yeah
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