Question

If the sum of zeroes of 3x^2-kx+6 is 3,the value of kis

Answer 1

Answer:

$sum \: of \: zeros \: = \alpha + \beta \\ \frac{ - b}{a} = \frac{3}{<strong>3</strong>} \\ p(x) = 3x {}^{2} - kx + 6 \\ \: \: \: \: \: \: \: \: \: = ax {}^{2} + bx + c \\ - k = b \\ k = 3$

Answer 2

Answer:

Value of k is 3