if the sum of zeros of quadratic polynomial 3x²-kx+6is 3 find the value of k
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Given
sum of the quadratic equation 3x²-kx+6 is 3
To Find
we have to find the value of k
We have quadratic equation: 3x²-kx+6
sum of zeroes = -b/a
a= 3 ,b= -k & c= 6
Sum of zeroes= -(-k/3)
Now,we have given sum of zeroes is 3
So, equate with the given value
=>sum of zeroes =3
=>-(-k/3)=3
=>k/3=3
=>k=3×3
=>k=9
Check:
=>3x²-kx+6
=>3x²-9x+6
=>x²-3x+2=0
=>x²-2x-x+2=0
=>x(x-2)-1(x-2)=0
=>(x-1)(x-2)=0
=>x=1,2
we have x= 1,2 and k =9
If the quadratic equation will be zero after putting X's value and k then it will be verified and hence ,k's value is correct.
=>3x²-kx+6
=>3(1)²-9(1)+6
=>3-9+6
=>-6+6=0
Or at x= 2
=>3(2)²-9(2)+6
=>12-18+6
=>-6+6=0
Verified✓
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