Question

If the sum of zeros of the quadratic polynomial 3x^2-kx + 6 is 3 ,find the value of k .​

Answer 1

Answer:

Answer : k = 9

Step-by-step explanation:

p(x) = 3x² - kx + 6

Sum of zeros = 3

-(Cofficient of x)/(Cofficient of x²)

3= - [- k / 3]

k = 9 Answer....

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Answer 2

Answer: given sum of zeroes =3

Here a=3 ,b= -k, c=6

As, alpha + beta = -b/a

So , 3 = -b/a

3 = -(-K)/3

3 = k/3

K = 9

Hence, value of k is 9.