If the sum to n terms pf an
a.P is sn=3n+2n2 then the common difference
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Answer:
Given,
Sn = 3n + 2n^2
so,
S1 = 3×1 + 2×1^2
S1 = 5
We know, S1 = a1
so a1 = 5
Now S2 = 3(2) +2(2)^2
S2 = 6 + 8 = 14
Also,
S2 = a1 + a2,
or, a2 = S2 - a1 = 14 - 5 = 9
Now, common diff. = a2 - a1 = 9 - 5 = 4.
Hence 4 is the common diff. of the given A.P.
I hope you understood. You may ask if you have doubts :)
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