Question

if the supplement of an angle is 3 times its complement find the angle

Answer 1

↑ Here is your answer ↓
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Let the angle be 'x',

Given that,

$3 (90^o - x) = 180^o - x$

$270^o - 3x = 180^o -x$

$270^o - 3x - 180^o + x = 0$

$90^o - 2x = 0$

$2x = 90^o$

$x = 90^o/2$

$x = 45^o$

Answer 2

Hey there!

Let the Measure of Angle be " p " .

Now,
Supplement of p = ( 180 - p)
Complement of p = ( 90- p )

With accordance to the question ,

180 - p = 3 ( 90 - p)

180 - p = 270 - 3p

3p - p = 270 - 180

2p = 90

p = 45°

Therefore, The angle is 45°