prove that : log 11÷5 + log 14÷3 - log22÷15 =log 7
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Answered by
18
⭐⭐Hello friend..Ur answer is here⤵⤵
⚫ log 11÷5 + log 14÷3 - log22÷15
➡log11/5+log14/3-log22/15
➡log11-log5+log14-log3-log22+log15
➡log11-log5+log7×2-log3-log11×2+log5×3
➡log11-log5+log7+log2-log3-log11-log2+log5+log3
➡Cancel the opposite sign term..we get
➡log7 HENCE PROVED
I hope it is helpful to you☺
⚫ log 11÷5 + log 14÷3 - log22÷15
➡log11/5+log14/3-log22/15
➡log11-log5+log14-log3-log22+log15
➡log11-log5+log7×2-log3-log11×2+log5×3
➡log11-log5+log7+log2-log3-log11-log2+log5+log3
➡Cancel the opposite sign term..we get
➡log7 HENCE PROVED
I hope it is helpful to you☺
krish444:
thanks
Answered by
4
Answer:
hope u have got the ans.....
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