Question

If the surface area of the spherical ball is 4n then find the length of the line joining center and point on its surface?​

Answer 1

Answer:

Surface area of a spherical ball = 4πr²

4n = 4πr²

4n*7/4*22 = r²

7n/22 = r²

√7n/22 = r

Therefore the length of the line joining center and point on its surface that is, it's radius =√7n/22

Or taking the value of π=3.14

4n= 4* 3.14*r²

4n/4*3.14= r²

n/3.14 = r²

√n/3.14= r

√n/ 1.772 = r

Answer 2

Given:

The surface area of a spherical ball=4n

To find:

The length of the line joining centre and point on its surface

Solution:

The length of the line joining centre and point on its surface is 0.56$\sqrt{n}$.

We can find the length by following the steps given below-

We know that the length of the line joining centre and point on its surface is the radius of the spherical ball.

Let the radius of the ball be r.

The surface area of the spherical ball=4π$r^{2}$

We are given that the surface area of the ball is equal to 4n.

So, 4n=4π$r^{2}$

n=π$r^{2}$

n/π=$r^{2}$

We will substitute the value of π as 22/7.

n/(22/7)=$r^{2}$

7n/22=$r^{2}$

$\sqrt{7n/22}$=r

0.56$\sqrt{n}$=r

Therefore, the length of the line joining centre and point on its surface is 0.56$\sqrt{n}$.