Question

If the system equation2x+3y=7,2ax+(a+b)y=28 has infinity many solution then find (a) a=2b (b)b=2a (c) a+2b=0 (d) 2a+b =0​

Answer 1

Answer:

(b) b = 2a

Step-by-step explanation:

Since the equations have infinite solutions,

$\frac{a1}{a2 } = \frac{b1}{b2} = \frac{c1}{c2 }$

therefore,

$\frac{2}{2a} = \frac{3}{a + b} = \frac{7}{28}$

We have,

$\frac{2}{2a} = \frac{7}{28}$

so,

$a = 4$

Now,

$\frac{3}{a + b} = \frac{7}{28}$

$\frac{3}{4 + b} = \frac{1}{4}$

Thus b= 8

Now it is obvious that b = 2a since 4 × 2 = 8

Hence b is the correct option