Question

if the system of equations 2x + 3y = 7 and 2ax + (a+b) y = 28 has infinitely many solutions,then

Answer 1

infinite many solution equation is--

a1/ a2 = b1/b2 = c1/c2

let [ a1=2 ,a2 =2a ,.b1=3 ,b2=(a+b) ,,c1=7,c2=28]

now we put the given equation

= 2/2a =3/(a+b) =7/28

= 1/a =3/(a+b) =1/4

then we cross multiply to find the value of a and b

= 1/4=1/a

= a= 4 ANS.

= 3/ a+b =1/4

= 12=a+b (a=4)

= 12 = 4+ b

= 12-4=b

= 8 =b ANS..

----- a= 4 ,,b =8

hope this helps u...