Question

if the system of equations 2x+ky=11 and 5x-7y=5has no solution,then find the value of k.

Answer 1

I hope it helps you...

Answer 2

Answer:

Concept: the equations which has no solution is defined as $\frac{a1}{a2} =\frac{b1}{b2} \neq \frac{c1}{c2 }$

Given: $5x-7y=5$ and $2x+ky=11$

To find: value of k.

Step-by-step explanation:

there are three types of solutions in the equations, they are as follows

1. unique solution
2. no solution
3. infinite many solutions

the given question is no solution so we will use the defined $\frac{a1}{a2} =\frac{b1}{b2} \neq \frac{c1}{c2 }$ as the base to solve the question.

And the equations are    $2x+ky=11$

                                     $5x-7y=5$

so, the question can be solve in two ways

one is $\frac{a1}{a2} =\frac{b1}{b2}$                                          and another is $\frac{b1}{b2} \neq \frac{c1}{c2 }$

so, $\frac{2}{5} =\frac{k}{-7}$                                                 or, $\frac{k}{-7} \neq \frac{11}{5}$

or, $k=\frac{-14}{5}$                                                  or, $k\neq \frac{-77}{5}$.

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