Question

If the system of equations 4x + ky+8= 0 and 2x + 2y +2=0 have an unique
solution, then
(A) k= 4
(B) k#4
(C) k#-4
(D) None of these​

Answer 1

k=4 is right answer by my thought

Answer 2

Answer:

Option  B - k#4

Step-by-step explanation:

Intersecting lines have a unique solution and ratios of the fractions are not equal.

$\frac{a1}{a2} \neq \frac{b1}{b2} \\\frac{4}{2} \neq \frac{k}{2} \\\\\frac{4 * 2}{2} \neq k\\\\k\neq 4$

This is satisfied only when k is not equal to 4. Therefore, your correct answer is option B.

Hope this helped!!