Question

If the third term of a gp is 4 then the product of its 5 terms is??

Answer 1

let the first term be a and ratio be r
Then ar^2=4
product of 5 terms = a ×ar .....ar^4 =a^5r^10
a^5r^10 =(ar^2)^5
from value of ar^2=4
ans = 4^5
=1024

Answer 2

Answer:

your solution is as follows

pls mark it as brainliest

Step-by-step explanation:

$to \: find : \\ product \: of \: first \: terms \: of \: \\ certain \: \\ \\ for \: a \: certain \: GP \\ let \: its \: first \: five \: terms \: be \\ a \: ,ar \: ,ar {}^{2} \: ar {}^{3} \: ,ar {}^{4} \\ \\ according \: to \: given \: condition \\ ar {}^{2} = 4 \\ \\ therefore \: then \\ a \times ar \times ar {}^{2} \times ar {}^{3} \times ar {}^{4} = k \\ \\ = a {}^{5} .r {}^{1 + 2 + 3 + 4} \\ \\ = a {}^{5} .r {}^{10} \\ \\ =( ar {}^{2} \: ) {}^{5} \\ \\ = (4) {}^{5} \\ \\ = 4 {}^{2} .4 {}^{2} .4 \\ \\ = 16 \times 16 \times 4 \\ \\ = 256 \times 4 \\ \\ k = 1024$